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Algorithm/백준/Gold/15989. 1, 2, 3 더하기 4/1, 2, 3 더하기 4.py

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Python

dp = [1] * 10001
for i in range(2, 10001):
dp[i] += dp[i - 2]
for i in range(3, 10001):
dp[i] += dp[i - 3]
t = int(input())
for _ in range(t):
n = int(input())
print(dp[n])